# Maths is the compulsory subject in different education field. It is also necessary for various jobs in Pakistan. We provides Mcqs bases online quiz in different topics such as Basic Maths, Numbers, Root & Cube, Equation, Fraction, Average, Triangle, Distance, Simplification, Ratio, Square Root, Percentage and Decimals etc which will help you to improve your knowledge. Attempt the Free Online Test Quiz below which is sequentially given according to different topics.

Maths Average Test.2

**Quiz Instructions:**

- There will be 20 multiple choice question in this online test.
- Answer of the questions will change randomly each time you start this test.
- Practice this test at least 3 times if you want to secure High Marks.
- At the End of the Test you can see your Test score and Rating.

1 / 20

**The temperature at noon in LHR ,Pakistan was 6 deg on Monday ,4deg on Tuesday,2deg below zero on Wednesday,3deg below zero on Thursday, 0 deg on Friday ,3 deg on Saturday ,and 6 deg on Sunday. What was the average temperature at noon for the week ?**

2 / 20

**The average of two numbers is XY.If one number is equal to X ,the other number is equal to_________?**

3 / 20

**If the average marks of three batches of 55, 60 and 45 students respectively is 50, 55, 60, then the average marks of all the students is__________?**

Required average = (55 x 50 + 60 x 55 + 45 x 60) / (55 + 60 + 45)

= (2750 + 3300 + 2700) /160

= **54.68 is correct Answer**

Required average = (55 x 50 + 60 x 55 + 45 x 60) / (55 + 60 + 45)

= (2750 + 3300 + 2700) /160

= **54.68 is correct Answer**

4 / 20

**The average weight of 16 boys in a class is 50.25 kg and that of the remaining 8 boys is 45.15 kg. Find the average weights of all the boys in the class.**

5 / 20

**The average weight of A, B and C is 45 kg. If the average weight of A and B be 40 kg and that of B and C be 43 kg, then the weight of B is___________?**

Let A, B, C represent their respective weights. Then, we have: A + B + C = (45 x 3) = 135 …. (i) A + B = (40 x 2) = 80 …. (ii) B + C = (43 x 2) = 86 ….(iii) Adding (ii) and (iii), we get: A + 2B + C = 166 …. (iv) Subtracting (i) from (iv), we get : B = 31. B’s weight = **31 kg**

Let A, B, C represent their respective weights. Then, we have: A + B + C = (45 x 3) = 135 …. (i) A + B = (40 x 2) = 80 …. (ii) B + C = (43 x 2) = 86 ….(iii) Adding (ii) and (iii), we get: A + 2B + C = 166 …. (iv) Subtracting (i) from (iv), we get : B = 31. B’s weight = **31 kg**

6 / 20

**The average of 18 observations was calculated and it was 124. Later on it was discovered that two observations 46 and 82 were incorrect. The correct values are 64 and 28. The correct average of 18 observations is___________?**

Sum of 18 observations = 18×124 =2232

Correct sum of 18 observations = 2232-46-82+64+28

= 2196

Therefore, Correct average =2196/18 = **122**

Sum of 18 observations = 18×124 =2232

Correct sum of 18 observations = 2232-46-82+64+28

= 2196

Therefore, Correct average =2196/18 = **122**

7 / 20

**A person travels from x to y at a speed of 40Km/h and returns by increasing his speed 50%. What is his average speed for both the trips?**

Explanation:

Speed of person from x to y =40 km/h

Speed of person from y to x =(40×150)/100 = 60km/h

Since the distance travelled is same

Therefore, Average Speed = (2x40x60)/40+60 = **48km/h**

Explanation:

Speed of person from x to y =40 km/h

Speed of person from y to x =(40×150)/100 = 60km/h

Since the distance travelled is same

Therefore, Average Speed = (2x40x60)/40+60 = **48km/h**

8 / 20

**The mean marks of 30 students in a class is 58.5. Later on it was found that 75 was wrongly recorded as 57. Find the correct them.**

Correct mean = 30x 58.5 -57 +75/30

= 1755+18/30 = 1773/30 = **59.1**

Correct mean = 30x 58.5 -57 +75/30

= 1755+18/30 = 1773/30 = **59.1**

9 / 20

**The average of women and child workers in a factory was 15%yr. The average age of all the 16 children was 8yr and average age of women workers was 22 yrs if ten women workers were married then the number of unmarried women workers were________?**

Let the number of women workers be x

According to the question 22*x+16*8 = 15(16+x)

=> 22x+128 =240 +15x

=> 22x-15x = 240 -128

=> 7x=112

Therefore, x=112/7 =16

Therefore, Unmarried women workers =(16-10) = **6**

Let the number of women workers be x

According to the question 22*x+16*8 = 15(16+x)

=> 22x+128 =240 +15x

=> 22x-15x = 240 -128

=> 7x=112

Therefore, x=112/7 =16

Therefore, Unmarried women workers =(16-10) = **6**

10 / 20

**In an examination a pupil’s average marks were 63 per paper. If he had obtained 20 more marks for his Geography paper and 2 more marks for his History paper, his average per paper would have been 65. How many papers were there in the examination?**

Let the number of papers be x. Then,

63x + 20 + 2 = 65x

= 2x = 22

= x = **11**

Let the number of papers be x. Then,

63x + 20 + 2 = 65x

= 2x = 22

= x = **11**

11 / 20

**The average age of students of a class is 15.8 years. The average age of boys in the class is 16.4 years and that of the girls is 15.4 years. The ration of the number of boys to the number of girls in the class is___________?**

Let the ratio be k : 1. Then,

k * 16.4 + 1 * 15.4 = (k + 1) * 15.8

= (16.4 – 15.8)k = (15.8 – 15.4)

= k = 0.4/0.6 = 2/3

Required ratio = 2/3 : 1 = **2:3**

Let the ratio be k : 1. Then,

k * 16.4 + 1 * 15.4 = (k + 1) * 15.8

= (16.4 – 15.8)k = (15.8 – 15.4)

= k = 0.4/0.6 = 2/3

Required ratio = 2/3 : 1 = **2:3**

12 / 20

**The average salary of all the workers in a workshop is Rs. 8000. The average salary of 7 technicians is Rs. 12000 and the average salary of the rest is Rs. 6000. The total number of workers in the workshop is__________________?**

Explanation:

Let the total number of workers be x. Then,

8000x = (12000 * 7) + 6000(x – 7)

= 2000x = 42000

= x = **21**

Explanation:

Let the total number of workers be x. Then,

8000x = (12000 * 7) + 6000(x – 7)

= 2000x = 42000

= x = **21**

13 / 20

**The average age of a husband, wife and their child 3 years ago was 27 years and that of wife and the child 5 years ago was 20 years. The present age of the husband is___________?**

Explanation:

Sum of the present ages of husband, wife and child = (23 * 2 + 5 * 2) = 57 years.

Required average = 57/3 = **19 years**

Explanation:

Sum of the present ages of husband, wife and child = (23 * 2 + 5 * 2) = 57 years.

Required average = 57/3 = **19 years**

14 / 20

**The arithmetic mean of the scores of a group of students in a test was 52. The brightest 20% of them secured a mean score of 80 and the dullest 25% a mean score of 31. The mean score of remaining 55% is___________?**

Explanation:

Let the required means score be x. Then,

20 * 80 + 25 * 31 + 55 * x = 52 * 100

= 1600 + 775 + 55x = 5200

= 55x = 2825

= x = 565/11 = **51.4.**

Explanation:

Let the required means score be x. Then,

20 * 80 + 25 * 31 + 55 * x = 52 * 100

= 1600 + 775 + 55x = 5200

= 55x = 2825

= x = 565/11 = **51.4.**

15 / 20

**A cricketer has a certain average for 10 innings. In the eleventh inning, he scored 108 runs, there by increasing his average by 6 runs. His new average is_____________?**

Explanation:

Let average for 10 innings be x. Then,

(10x + 108)/11 = x + 6

= 11x + 66 = 10x + 108

= x = 42.

New average = (x + 6) = **48 runs**

Explanation:

Let average for 10 innings be x. Then,

(10x + 108)/11 = x + 6

= 11x + 66 = 10x + 108

= x = 42.

New average = (x + 6) = **48 runs**

16 / 20

**The captain of a cricket team of 11 members is 26 years old and the wicket keeper is 3 years older. If the ages of these two are excluded, the average age of the remaining players is one year less than the average age of the whole team. What is the average of the team?**

Explanation:

Let the average of the whole team be x years.

11x – (26 + 29) = 9(x – 1)

= 11x – 9x = 46

= 2x = 46 => x = 23

So, average age of the team is **23 years**

Explanation:

Let the average of the whole team be x years.

11x – (26 + 29) = 9(x – 1)

= 11x – 9x = 46

= 2x = 46 => x = 23

So, average age of the team is **23 years**

17 / 20

**The average monthly salary of 20 employees in an organisation is Rs. 1500. If the manager’s salary is added, then the average salary increases by Rs. 100. What is the manager’s monthly salary?**

Explanation:

Manager’s monthly salary

= Rs. (1600 * 21 – 1500 * 20) = **Rs. 3600**

Explanation:

Manager’s monthly salary

= Rs. (1600 * 21 – 1500 * 20) = **Rs. 3600**

18 / 20

**The average monthly income of P and Q is Rs. 5050. The average monthly income of Q and R is 6250 and the average monthly income of P and R is Rs. 5200. The monthly income of P is____________?**

Explanation:

Let P, Q and R represent their respective monthly incomes. Then, we have:

P + Q = (5050 * 2) = 10100 — (i)

Q + R = (6250 * 2) = 12500 — (ii)

P + R = (5200 * 2) = 10400 — (iii)

Adding (i), (ii) and (iii), we get:

2(P + Q + R) = 33000 = P + Q + R = 16500 — (iv)

Subtracting (ii) from (iv), we get, P = 4000.

P’s monthly income = Rs. 4000

Explanation:

Let P, Q and R represent their respective monthly incomes. Then, we have:

P + Q = (5050 * 2) = 10100 — (i)

Q + R = (6250 * 2) = 12500 — (ii)

P + R = (5200 * 2) = 10400 — (iii)

Adding (i), (ii) and (iii), we get:

2(P + Q + R) = 33000 = P + Q + R = 16500 — (iv)

Subtracting (ii) from (iv), we get, P = 4000.

P’s monthly income = Rs. 4000

19 / 20

**The average weight of A, B and C is 45 kg. If the average weight of A and B be 40 kg and that of B and C be 43 kg, then the weight of B is___________?**

Explanation:

Let A, B, C represent their respective weights.

Then, we have:

A + B + C = (45 * 3) = 135 — (i)

A + B = (40 * 2) = 80 — (ii)

B + C = (43 * 2) = 86 — (iii)

Adding (ii) and (iii), we get: A + 2B + C = 166 — (iv)

Subtracting (i) from (iv), we get: B = 31

B’s weight = **31 kg**

Explanation:

Let A, B, C represent their respective weights.

Then, we have:

A + B + C = (45 * 3) = 135 — (i)

A + B = (40 * 2) = 80 — (ii)

B + C = (43 * 2) = 86 — (iii)

Adding (ii) and (iii), we get: A + 2B + C = 166 — (iv)

Subtracting (i) from (iv), we get: B = 31

B’s weight = **31 kg**

20 / 20

**The average age of 15 students of a class is 15 years. Out of these, the average age of 5 students is 14 years and that of the other 9 students is 16 years. The age of the 15th student is____________?**

Explanation:

Age of the 15th student=

[15 * 15 – (14 * 5 + 16 * 9)] = (225 – 214) = **11 years**

Explanation:

Age of the 15th student=

[15 * 15 – (14 * 5 + 16 * 9)] = (225 – 214) = **11 years**